Chemical Kinetics · Class 12 · CBSE · Science Chemistry

The activation energy of a reaction can be determined graphically by plotting:

Practice question from Chemical Kinetics (Class 12 · CBSE · Science Chemistry), with the correct answer and a step-by-step solution.

medium · MCQ · Q-056C55

The activation energy of a reaction can be determined graphically by plotting:

  1. A.ln⁡k\ln k vs TT
  2. B.kk vs 1/T1/T
  3. C.ln⁡k\ln k vs 1/T1/TCorrect answer
  4. D.TT vs ln⁡k\ln k

Solution

According to the Arrhenius equation, ln⁡k=ln⁡A−EaR(1T)\ln k = \ln A - \frac{E_a}{R}\left(\frac{1}{T}\right). A plot of ln⁡k\ln k versus 1/T1/T gives a straight line with a slope of −Ea/R-E_a/R.

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