Structure of Atom · JEE Preparation Chemistry

The correct set of four quantum numbers for the outermost electron of a Sodium atom (atomic number 11) is:

Practice question from Structure of Atom (JEE Preparation Chemistry), with the correct answer and a step-by-step solution.

medium · MCQ · Q-17F898

The correct set of four quantum numbers for the outermost electron of a Sodium atom (atomic number 11) is:

  1. A.3, 0, 0, +1/2Correct answer
  2. B.3, 1, 0, +1/2
  3. C.3, 0, 1, +1/2
  4. D.2, 0, 0, +1/2

Solution

Sodium (Z=11Z = 11) has the electronic configuration 1s22s22p63s11s^2 2s^2 2p^6 3s^1. The outermost electron is in the 3s3s orbital. For 3s3s, n=3n = 3, l=0l = 0, m=0m = 0, and spin quantum number s=+1/2s = +1/2.

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