Alternating Current · NEET Preparation Physics

In a series LCR circuit, the resonant frequency is f0. If both the inductance and capacitance are doubled, the new resonant frequency becomes:

Practice question from Alternating Current (NEET Preparation Physics), with the correct answer and a step-by-step solution.

medium · MCQ · Q-3074FD

In a series LCR circuit, the resonant frequency is f0f_0. If both the inductance and capacitance are doubled, the new resonant frequency becomes:

  1. A.2 f_0
  2. B.\frac{f_0}{2}Correct answer
  3. C.\sqrt{2} f_0
  4. D.\frac{f_0}{\sqrt{2}}

Solution

The resonant frequency of a series LCR circuit is given by f0=12πLCf_0 = \frac{1}{2\pi \sqrt{LC}}. When LL becomes 2L2L and CC becomes 2C2C, the new resonant frequency is f0′=12π(2L)(2C)=12π4LC=12×2πLC=f02f'_0 = \frac{1}{2\pi \sqrt{(2L)(2C)}} = \frac{1}{2\pi \sqrt{4LC}} = \frac{1}{2 \times 2 \pi \sqrt{LC}} = \frac{f_0}{2}.

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