Organic Chemistry – Some Basic Principles and Techniques · NEET Preparation Chemistry
In Carius method of estimation of halogens, 0.25 g of an organic compound gave 0.188 g of AgBr. The percentage of bromine in the compound is: (Atomic…
Practice question from Organic Chemistry – Some Basic Principles and Techniques (NEET Preparation Chemistry), with the correct answer and a step-by-step solution.
hard · MCQ · Q-572016
In Carius method of estimation of halogens, 0.25 g of an organic compound gave 0.188 g of AgBr. The percentage of bromine in the compound is: (Atomic mass of Ag = 108, Br = 80 g/mol)
- A.32.0%Correct answer
- B.16.0%
- C.64.0%
- D.48.0%
Solution
Molar mass of AgBr = 108 + 80 = 188 g/mol. Mass of AgBr formed = 0.188 g. Percentage of Br = (Atomic mass of Br / Molar mass of AgBr) * (Mass of AgBr formed / Mass of organic compound) * 100 = (80 / 188) * (0.188 / 0.25) * 100 = (80 / 188) * 0.75 * 100 = 32.0%.
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