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Binomial Theorem · JEE Preparation Mathematics

What is the coefficient of x^2 in the expansion of (3x - 2)^5?

Practice question from Binomial Theorem (JEE Preparation Mathematics), with the correct answer and a step-by-step solution.

easy · MCQ · Q-9BA777

What is the coefficient of x^2 in the expansion of (3x - 2)^5?

  1. A.-720Correct answer
  2. B.-240
  3. C.720
  4. D.240

Solution

The required term is (52)(3x)2(−2)3\binom{5}{2}(3x)^2(-2)^3. Hence, the coefficient of x2x^2 is (52)×32×(−2)3=10×9×(−8)=−720\binom{5}{2}\times 3^2\times(-2)^3=10\times9\times(-8)=-720.

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