Work, Energy and Power · NEET Preparation Physics
The potential energy of a particle of mass 1text{ kg} moving along the x-axis is given by U(x) = frac{x^2}{2} - x. The equilibrium position of the pa…
Practice question from Work, Energy and Power (NEET Preparation Physics), with the correct answer and a step-by-step solution.
medium · MCQ · Q-9FE978
The potential energy of a particle of mass moving along the x-axis is given by . The equilibrium position of the particle is at:
- A.x = 0
- B.x = 1 mCorrect answer
- C.x = -1 m
- D.x = 2 m
Solution
For equilibrium, the force must be zero, which means . Given , differentiating with respect to gives . Setting this equal to zero gives .
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