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Force and Laws of Motion · Class 9 · CBSE Science

A constant force acts on an object of mass 5 kg at rest for 2 seconds, giving it a velocity of 6 m s^-1. The magnitude of the force is:

Practice question from Force and Laws of Motion (Class 9 · CBSE Science), with the correct answer and a step-by-step solution.

medium · MCQ · Q-AA1A57

A constant force acts on an object of mass 5 kg at rest for 2 seconds, giving it a velocity of 6 m s^-1. The magnitude of the force is:

  1. A.15 NCorrect answer
  2. B.30 N
  3. C.12 N
  4. D.7.5 N

Solution

Acceleration a=(v−u)/t=(6−0)/2=3a = (v - u) / t = (6 - 0) / 2 = 3 m s^-2. Force F=m×a=5 kg×3 m s−2=15F = m \times a = 5 \text{ kg} \times 3 \text{ m s}^{-2} = 15 N.

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