Introduction to Trigonometry · Class 10 · CBSE Mathematics

Evaluate: 9 sec^2 A - 9 tan^2 A.

Practice question from Introduction to Trigonometry (Class 10 · CBSE Mathematics), with the correct answer and a step-by-step solution.

easy · MCQ · Q-AA3FD1

Evaluate: 9sec⁡2A−9tan⁡2A9 \sec^2 A - 9 \tan^2 A.

  1. A.11
  2. B.99Correct answer
  3. C.88
  4. D.00

Solution

Taking 9 common from the expression, we get 9(sec⁡2A−tan⁡2A)9(\sec^2 A - \tan^2 A). Since sec⁡2A−tan⁡2A=1\sec^2 A - \tan^2 A = 1 for any angle AA, the expression evaluates to 9(1)=99(1) = 9.

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