Laws of Motion · NEET Preparation Physics
A 2 kg block rests on a rough horizontal surface. The coefficient of static friction is 0.4, and g = 10 m/s². If a horizontal force of 6 N is applied…
Practice question from Laws of Motion (NEET Preparation Physics), with the correct answer and a step-by-step solution.
easy · MCQ · Q-BA9910
A 2 kg block rests on a rough horizontal surface. The coefficient of static friction is 0.4, and g = 10 m/s². If a horizontal force of 6 N is applied to the block, the frictional force on it is
- A.0 N
- B.6 NCorrect answer
- C.8 N
- D.20 N
Solution
The maximum static friction is μsN = 0.4 × 2 × 10 = 8 N. Since the applied force is only 6 N, static friction adjusts to 6 N in the opposite direction, keeping the block at rest.
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