Electromagnetic Waves · NEET Preparation Physics

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0 = 510 text{ nT}. What is the amplitude of the electric fi…

Practice question from Electromagnetic Waves (NEET Preparation Physics), with the correct answer and a step-by-step solution.

medium · MCQ · Q-C14B9F

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0=510 nTB_0 = 510 \text{ nT}. What is the amplitude of the electric field part of the wave?

  1. A.153 N/CCorrect answer
  2. B.306 N/C
  3. C.1.7 N/C
  4. D.510 N/C

Solution

The relation between the amplitudes of electric and magnetic fields in an electromagnetic wave is given by E0=cB0E_0 = c B_0. Substituting c=3×108 m/sc = 3 \times 10^8 \text{ m/s} and B0=510×10−9 TB_0 = 510 \times 10^{-9} \text{ T}, we get E0=(3×108)×(510×10−9)=153 N/CE_0 = (3 \times 10^8) \times (510 \times 10^{-9}) = 153 \text{ N/C}.

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