An athlete completes one round of a circular track of diameter d in 40text{ s}. What will be the displacement at the end of 2text{ minutes } 20text{…

Total time $= 2\text{ min } 20\text{ s} = 140\text{ s}$. Number of rounds $= 140 / 40 = 3.5$ rounds. After 3 complete rounds, the athlete is back at the starting point. In the remaining $0.5$ round, the athlete reaches the diametrically opposite point, so the displacement equals the diameter, $d$.