Introduction to Three Dimensional Geometry · Class 11 · CBSE · Science Mathematics

The distance between the points P(1, -2, 3) and Q(4, 2, -1) is:

Practice question from Introduction to Three Dimensional Geometry (Class 11 · CBSE · Science Mathematics), with the correct answer and a step-by-step solution.

medium · MCQ · Q-CA6252

The distance between the points P(1, -2, 3) and Q(4, 2, -1) is:

  1. A.√17 units
  2. B.√41 unitsCorrect answer
  3. C.7 units
  4. D.9 units

Solution

Using the three-dimensional distance formula, PQ=(4−1)2+(2+2)2+(−1−3)2=9+16+16=41PQ=\sqrt{(4-1)^2+(2+2)^2+(-1-3)^2}=\sqrt{9+16+16}=\sqrt{41} units.

More from Introduction to Three Dimensional Geometry

All of Introduction to Three Dimensional Geometry

Practise more Mathematics

Sign up free for adaptive practice on this chapter, with instant feedback and hints on every question.

Start practising free

Free to start · No credit card needed