Inverse Trigonometric Functions · Class 12 · CBSE · Science Mathematics
Evaluate cos⁻¹(cos(7π/6)) using the principal value of cos⁻¹.
Practice question from Inverse Trigonometric Functions (Class 12 · CBSE · Science Mathematics), with the correct answer and a step-by-step solution.
hard · MCQ · Q-E1EB59
Evaluate cos⁻¹(cos(7π/6)) using the principal value of cos⁻¹.
- A.π/6
- B.5π/6Correct answer
- C.7π/6
- D.−5π/6
Solution
Since cos(7π/6) = −√3/2 and the principal range of cos⁻¹ is [0, π], we need the angle in this interval having cosine −√3/2. Therefore, cos⁻¹(cos(7π/6)) = 5π/6.
More from Inverse Trigonometric Functions
- Using the principal value of the inverse sine function, find sin⁻¹(−√3/2).
- For the function f(x) = cos⁻¹(2x − 1), which of the following gives its domain and range?
- Evaluate sin⁻¹(3/5) + sin⁻¹(4/5), and justify your answer using the principal-value ranges.
- Using the principal value of the inverse tangent function, find tan⁻¹(−√3).
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