Chapter 2 · Class 12 · CBSE · Science Physics

Electrostatic Potential and Capacitance

🔌 Chapter 3: Current Electricity (⚡ Electric Current • 🚶 Drift Velocity • 📏 Ohm's Law • 📊 V-I Characteristics • 🔥 Power & Energy • 🧱 Resistance • 🔋 EMF & Cells • 🔀 Kirchhoff's Rules • 🌉 Wheatstone Bridge)

35 practice questions · 7 marks weightage

Topics in this chapter

  • Electrostatic Potential And Fields
  • Spherical Charge Distributions
  • Dipole Potential And Interactions
  • Capacitor Combinations And Networks
  • Dielectrics In Capacitors
  • Capacitor Energy And Transients

Cheat sheet

Cheat Sheet

Practice questions

  1. Question 1Q-2CCD39

    What is the amount of work done in moving a test charge of 2×10−9 C2 \times 10^{-9}\text{ C} along an equipotential surface from a point A to a point B separated by a distance of 5 cm5\text{ cm}?

    1. A.10−10 J10^{-10}\text{ J}
    2. B.Zero
    3. C.10−8 J10^{-8}\text{ J}
    4. D.4 J4\text{ J}
    See the answer and solution
  2. Question 2Q-5ECBCC

    A parallel plate capacitor with air between the plates has a capacitance CC. If the distance between the plates is doubled and the space between them is filled with a dielectric medium of dielectric constant K=4K = 4, the new capacitance will be:

    1. A.2C2C
    2. B.4C
    3. C.C/2C/2
    4. D.8C8C
    See the answer and solution
  3. Question 3Q-8527FB

    Four capacitors of capacitances 2 μF,4 μF,6 μF2\,\mu\text{F}, 4\,\mu\text{F}, 6\,\mu\text{F}, and 12 μF12\,\mu\text{F} are connected in parallel. If the combination is connected across a 100 V100\text{ V} supply, the total charge stored in the combination is:

    1. A.2400 μC2400\,\mu\text{C}
    2. B.1200 μC1200\,\mu\text{C}
    3. C.600 μC600\,\mu\text{C}
    4. D.24 μC24\,\mu\text{C}
    See the answer and solution
  4. Question 4Q-8B62A6

    An electric dipole of dipole moment PP is placed in a uniform electric field EE with its axis making an angle of 60∘60^{\circ} with the field. The potential energy of the dipole is:

    1. A.−32PE-\frac{\sqrt{3}}{2}PE
    2. B.−PE2-\frac{PE}{2}
    3. C.PE2\frac{PE}{2}
    4. D.−PE-PE
    See the answer and solution
  5. Question 5Q-54D74E

    The electric potential at any point (x,y,z)(x, y, z) in space is given by V=3x2+yV = 3x^2 + y, where VV is in volts and x,yx, y are in meters. The magnitude of the electric field at the point (1 m,2 m,0 m)(1\text{ m}, 2\text{ m}, 0\text{ m}) is:

    1. A.6 V/m6\text{ V/m}
    2. B.7 V/m7\text{ V/m}
    3. C.37 V/m\sqrt{37}\text{ V/m}
    4. D.3 V/m3\text{ V/m}
    See the answer and solution

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