What is the nuclear density of a nucleus having mass number A, given that R0 = 1.2 times 10^{-15}text{ m} and the average mass of a nucleon is 1.67 t…

Nuclear density $\rho = \frac{\text{Mass}}{\text{Volume}} = \frac{A m}{(4/3)\pi R_0^3 A} = \frac{3m}{4\pi R_0^3}$. Substituting the values, $\rho = \frac{3 \times 1.67 \times 10^{-27}}{4 \times 3.14 \times (1.2 \times 10^{-15})^3} \approx 2.3 \times 10^{17}\text{ kg m}^{-3}$. Notice that density is independent of mass number $A$.