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Nuclei · Class 12 · CBSE · Science Physics

The radius of a nucleus of mass number A is given by R = R0 A^{1/3}. If the radius of an aluminium nucleus ({13}^{27} ext{Al}) is 3.6 ext{ fm}, the e…

Practice question from Nuclei (Class 12 · CBSE · Science Physics), with the correct answer and a step-by-step solution.

easy · MCQ · Q-813D5B

The radius of a nucleus of mass number AA is given by R=R0A1/3R = R_0 A^{1/3}. If the radius of an aluminium nucleus (1327extAl_{13}^{27} ext{Al}) is 3.6extfm3.6 ext{ fm}, the estimated radius of a tellurium nucleus (52125extTe_{52}^{125} ext{Te}) is:

  1. A.5.0 fm5.0\text{ fm}
  2. B.6.0 fm6.0\text{ fm}Correct answer
  3. C.4.5 fm4.5\text{ fm}
  4. D.3.6 fm3.6\text{ fm}

Solution

The nuclear radius is directly proportional to A1/3A^{1/3}. Therefore, RTe/RAl=(125/27)1/3=5/3R_{\text{Te}} / R_{\text{Al}} = (125 / 27)^{1/3} = 5/3. Thus, RTe=(5/3)×3.6 fm=6.0 fmR_{\text{Te}} = (5/3) \times 3.6\text{ fm} = 6.0\text{ fm}.

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