Oscillations · JEE Preparation Physics

Two identical springs of spring constant k are connected in series. The effective spring constant of the combination is:

Practice question from Oscillations (JEE Preparation Physics), with the correct answer and a step-by-step solution.

easy · MCQ · Q-277A8B

Two identical springs of spring constant kk are connected in series. The effective spring constant of the combination is:

  1. A.2k
  2. B.k/2Correct answer
  3. C.\sqrt{2}k
  4. D.k/4

Solution

For two springs in series, the effective spring constant keffk_{eff} is given by 1keff=1k+1k=2k\frac{1}{k_{eff}} = \frac{1}{k} + \frac{1}{k} = \frac{2}{k}. Thus, keff=k2k_{eff} = \frac{k}{2}.

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