Real Numbers · Class 10 · CBSE Mathematics

Given that text{HCF}(306, 657) = 9, find text{LCM}(306, 657).

Practice question from Real Numbers (Class 10 · CBSE Mathematics), with the correct answer and a step-by-step solution.

medium · MCQ · Q-2B577F

Given that HCF(306,657)=9\text{HCF}(306, 657) = 9, find LCM(306,657)\text{LCM}(306, 657).

  1. A.22338Correct answer
  2. B.22138
  3. C.22392
  4. D.22528

Solution

We know that for any two positive integers aa and bb, HCF(a,b)×LCM(a,b)=a×b\text{HCF}(a, b) \times \text{LCM}(a, b) = a \times b. Substituting the values: 9×LCM(306,657)=306×6579 \times \text{LCM}(306, 657) = 306 \times 657. LCM=306×6579=34×657=22338\text{LCM} = \frac{306 \times 657}{9} = 34 \times 657 = 22338.

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