Motion in a Straight Line · NEET Preparation Physics

The position of a particle moving along the x-axis is given by x = 3t^2 - 2t^3, where x is in meters and t is in seconds. The time at which the parti…

Practice question from Motion in a Straight Line (NEET Preparation Physics), with the correct answer and a step-by-step solution.

easy · MCQ · Q-2F94F6

The position of a particle moving along the x-axis is given by x=3t2−2t3x = 3t^2 - 2t^3, where xx is in meters and tt is in seconds. The time at which the particle achieves zero acceleration is:

  1. A.0.5 sCorrect answer
  2. B.1.0 s
  3. C.1.5 s
  4. D.2.0 s

Solution

Velocity v=dxdt=6t−6t2v = \frac{dx}{dt} = 6t - 6t^2. Acceleration a=dvdt=6−12ta = \frac{dv}{dt} = 6 - 12t. Setting a=0a = 0 gives 6−12t=0  ⟹  t=0.5 s6 - 12t = 0 \implies t = 0.5\text{ s}.

More from Motion in a Straight Line

All of Motion in a Straight Line

Practise more Physics

Sign up free for adaptive practice on this chapter, with instant feedback and hints on every question.

Start practising free

Free to start · No credit card needed