Motion in a Straight Line · NEET Preparation Physics

A body is dropped from a height H above the ground. If it takes T seconds to reach the ground, its position after time T/2 from the start is:

Practice question from Motion in a Straight Line (NEET Preparation Physics), with the correct answer and a step-by-step solution.

medium · MCQ · Q-7E2A14

A body is dropped from a height HH above the ground. If it takes TT seconds to reach the ground, its position after time T/2T/2 from the start is:

  1. A.H/4 above the ground
  2. B.3H/4 above the groundCorrect answer
  3. C.H/2 above the ground
  4. D.H/8 above the ground

Solution

Total height H=12gT2H = \frac{1}{2}gT^2. Distance fallen in time t=T/2t = T/2 is y=12g(T/2)2=12gT24=H4y = \frac{1}{2}g(T/2)^2 = \frac{1}{2}g\frac{T^2}{4} = \frac{H}{4}. Therefore, the position above the ground is H−H4=3H4H - \frac{H}{4} = \frac{3H}{4}.

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