If the 2nd term of an AP is 13 and the 5th term is 25, what is its 7th term?

We are given $a_2 = a + d = 13$ and $a_5 = a + 4d = 25$. Subtracting the first equation from the second gives $3d = 12$, so $d = 4$. Substituting $d = 4$ into $a + d = 13$ gives $a = 9$. The 7th term is $a_7 = a + 6d = 9 + 6(4) = 9 + 24 = 33$. Thus, the correct option is B.