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Electrochemistry · Class 12 · CBSE · Science Chemistry

For the cell reaction: Zn(s) + Cu^{2+}(aq) rightarrow Zn^{2+}(aq) + Cu(s), the representation of the cell is correctly given as:

Practice question from Electrochemistry (Class 12 · CBSE · Science Chemistry), with the correct answer and a step-by-step solution.

medium · MCQ · Q-3C99DB

For the cell reaction: \Zn(s)+Cu2+(aq)→Zn2+(aq)+Cu(s)\Zn(s) + Cu^{2+}(aq) \rightarrow Zn^{2+}(aq) + Cu(s), the representation of the cell is correctly given as:

  1. A.Cu(s)∣Cu2+(aq)∣∣Zn2+(aq)∣Zn(s)Cu(s) | Cu^{2+}(aq) || Zn^{2+}(aq) | Zn(s)
  2. B.Zn(s)∣Zn2+(aq)∣∣Cu2+(aq)∣Cu(s)Zn(s) | Zn^{2+}(aq) || Cu^{2+}(aq) | Cu(s)Correct answer
  3. C.Zn2+(aq)∣Zn(s)∣∣Cu(s)∣Cu2+(aq)Zn^{2+}(aq) | Zn(s) || Cu(s) | Cu^{2+}(aq)
  4. D.Cu2+(aq)∣Cu(s)∣∣Zn(s)∣Zn2+(aq)Cu^{2+}(aq) | Cu(s) || Zn(s) | Zn^{2+}(aq)

Solution

In cell representation, the anode (oxidation) is written on the left with a single vertical line separating phases, and the cathode (reduction) is written on the right. A double vertical line represents the salt bridge. Thus, Zn(s)∣Zn2+(aq)∣∣Cu2+(aq)∣Cu(s)Zn(s) | Zn^{2+}(aq) || Cu^{2+}(aq) | Cu(s).

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