Straight Lines · JEE Preparation Mathematics

Which equation represents the line passing through (3, -2) and perpendicular to the line 2x + 3y - 5 = 0?

Practice question from Straight Lines (JEE Preparation Mathematics), with the correct answer and a step-by-step solution.

medium · MCQ · Q-5AE9E6

Which equation represents the line passing through (3, -2) and perpendicular to the line 2x + 3y - 5 = 0?

  1. A.3x - 2y - 13 = 0Correct answer
  2. B.2x + 3y + 12 = 0
  3. C.3x + 2y - 5 = 0
  4. D.2x - 3y + 12 = 0

Solution

The given line has slope −23-\frac{2}{3}, so a perpendicular line has slope 32\frac{3}{2}. Using the point-slope form, y+2=32(x−3)y+2=\frac{3}{2}(x-3), which simplifies to 3x−2y−13=03x-2y-13=0.

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