Straight Lines · JEE Preparation Mathematics

What is the distance between the parallel lines 3x - 4y + 7 = 0 and 6x - 8y - 5 = 0?

Practice question from Straight Lines (JEE Preparation Mathematics), with the correct answer and a step-by-step solution.

hard · MCQ · Q-C4BB97

What is the distance between the parallel lines 3x - 4y + 7 = 0 and 6x - 8y - 5 = 0?

  1. A.9/5
  2. B.19/10Correct answer
  3. C.5/2
  4. D.19/5

Solution

Rewrite the second equation as 3x−4y−52=03x-4y-\frac{5}{2}=0. The distance is ∣7−(−5/2)∣32+(−4)2=19/25=1910\frac{|7-(-5/2)|}{\sqrt{3^2+(-4)^2}}=\frac{19/2}{5}=\frac{19}{10}.

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