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Ray Optics and Optical Instruments · Class 12 · CBSE · Science Physics

The critical angle for a medium is 30^circ. The speed of light in this medium is:

Practice question from Ray Optics and Optical Instruments (Class 12 · CBSE · Science Physics), with the correct answer and a step-by-step solution.

easy · MCQ · Q-7DB368

The critical angle for a medium is 30∘30^\circ. The speed of light in this medium is:

  1. A.1.5×108 m/s1.5 \times 10^8\text{ m/s}Correct answer
  2. B.3×108 m/s3 \times 10^8\text{ m/s}
  3. C.2×108 m/s2 \times 10^8\text{ m/s}
  4. D.1×108 m/s1 \times 10^8\text{ m/s}

Solution

The refractive index μ=1/sin⁡(C)=1/sin⁡(30∘)=2\mu = 1 / \sin(C) = 1 / \sin(30^\circ) = 2. The speed of light in the medium is v=c/μ=(3×108)/2=1.5×108 m/sv = c / \mu = (3 \times 10^8) / 2 = 1.5 \times 10^8\text{ m/s}.

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