Ray Optics and Optical Instruments · Class 12 · CBSE · Science Physics

A convex lens of focal length 20 cm is made of glass of refractive index 1.5. When it is immersed in a liquid of refractive index 1.33, its focal len…

Practice question from Ray Optics and Optical Instruments (Class 12 · CBSE · Science Physics), with the correct answer and a step-by-step solution.

medium · MCQ · Q-868451

A convex lens of focal length 20 cm is made of glass of refractive index 1.5. When it is immersed in a liquid of refractive index 1.33, its focal length becomes approximately:

  1. A.20 cm
  2. B.40 cm
  3. C.78 cmCorrect answer
  4. D.10 cm

Solution

Lens maker's formula is 1/f=(μgl−1)(1/R1−1/R2)1/f = (\mu_{gl} - 1)(1/R_1 - 1/R_2). When immersed in liquid, 1/fm=((μgl/μm)−1)(1/R1−1/R2)1/f_m = ((\mu_{gl}/\mu_m) - 1)(1/R_1 - 1/R_2). Taking the ratio: fm/f=(μgl−1)/((μgl/μm)−1)=(1.5−1)/((1.5/1.33)−1)≈0.5/0.128≈3.9f_m/f = (\mu_{gl} - 1) / ((\mu_{gl}/\mu_m) - 1) = (1.5 - 1) / ((1.5/1.33) - 1) \approx 0.5 / 0.128 \approx 3.9. Thus fm≈3.9×20=78 cmf_m \approx 3.9 \times 20 = 78\text{ cm}.

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