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Wave Optics · Class 12 · CBSE · Science Physics

The Brewster's angle for a transparent medium is 60^{circ}. The refractive index of the medium is:

Practice question from Wave Optics (Class 12 · CBSE · Science Physics), with the correct answer and a step-by-step solution.

easy · MCQ · Q-90B553

The Brewster's angle for a transparent medium is 60∘60^{\circ}. The refractive index of the medium is:

  1. A.3\sqrt{3}Correct answer
  2. B.1/31 / \sqrt{3}
  3. C.3/23 / 2
  4. D.2/32 / \sqrt{3}

Solution

According to Brewster's law, the refractive index μ=tan⁡(ip)\mu = \tan(i_p), where ipi_p is the Brewster's angle. Here ip=60∘i_p = 60^{\circ}, so μ=tan⁡(60∘)=3\mu = \tan(60^{\circ}) = \sqrt{3}.

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