A solid piece of iron in the form of a cuboid of dimensions 49 text{ cm} times 33 text{ cm} times 24 text{ cm} is molded to form a solid sphere. What…

Volume of the cuboid = $49 \times 33 \times 24 \text{ cm}^3$. Volume of the sphere = $\frac{4}{3} \pi r^3$. Equating the volumes: $\frac{4}{3} \times \frac{22}{7} \times r^3 = 49 \times 33 \times 24$. Solving for $r^3$, we get $r^3 = \frac{49 \times 33 \times 24 \times 3 \times 7}{4 \times 22} = 7^3 \times 3^3$, which gives $r = 21 \text{ cm}$.