How many solid spherical bullets, each of diameter 4 text{ cm}, can be made out of a solid rectangular lead block of dimensions 22 text{ cm} times 12…

Volume of rectangular block = $22 \times 12 \times 5 = 1320 \text{ cm}^3$. Radius of each spherical bullet = $2 \text{ cm}$. Volume of one bullet = $\frac{4}{3} \times \frac{22}{7} \times (2)^3 = \frac{704}{21} \text{ cm}^3$. Number of bullets = $\frac{\text{Volume of block}}{\text{Volume of one bullet}} = \frac{1320 \times 21}{704} = 315$.