Kinetic Theory · JEE Preparation Physics

Find the ratio of the root mean square speeds of oxygen molecules (O2) and ozone molecules (O3) at the same temperature.

Practice question from Kinetic Theory (JEE Preparation Physics), with the correct answer and a step-by-step solution.

easy · MCQ · Q-AAC8DC

Find the ratio of the root mean square speeds of oxygen molecules (O2O_2) and ozone molecules (O3O_3) at the same temperature.

  1. A.32\sqrt{\frac{3}{2}}Correct answer
  2. B.23\sqrt{\frac{2}{3}}
  3. C.32\frac{3}{2}
  4. D.35\sqrt{\frac{3}{5}}

Solution

The root mean square speed is inversely proportional to the square root of the molar mass (vrms∝1Mv_{rms} \propto \frac{1}{\sqrt{M}}). For oxygen (M1=32M_1 = 32) and ozone (M2=48M_2 = 48), the ratio is v1v2=M2M1=4832=32\frac{v_1}{v_2} = \sqrt{\frac{M_2}{M_1}} = \sqrt{\frac{48}{32}} = \sqrt{\frac{3}{2}}.

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