Evolution · NEET Preparation Zoology
In a large, randomly mating population at Hardy–Weinberg equilibrium, 9% of individuals show a recessive phenotype. What percentage of the population…
Practice question from Evolution (NEET Preparation Zoology), with the correct answer and a step-by-step solution.
medium · MCQ · Q-AFD22D
In a large, randomly mating population at Hardy–Weinberg equilibrium, 9% of individuals show a recessive phenotype. What percentage of the population is expected to be heterozygous?
- A.21%
- B.42%Correct answer
- C.49%
- D.70%
Solution
The recessive phenotype frequency is q² = 0.09, so q = 0.3 and p = 0.7. The heterozygous frequency is 2pq = 2 × 0.7 × 0.3 = 0.42, or 42%.
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