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Some Basic Concepts of Chemistry · Class 11 · CBSE · Science Chemistry

Calculate the mass percentage of carbon in ethanol (C2H5OH). (Atomic masses: C = 12 text{ g mol}^{-1}, H = 1 text{ g mol}^{-1}, O = 16 text{ g mol}^{…

Practice question from Some Basic Concepts of Chemistry (Class 11 · CBSE · Science Chemistry), with the correct answer and a step-by-step solution.

medium · MCQ · Q-B83D04

Calculate the mass percentage of carbon in ethanol (C2H5OHC_2H_5OH). (Atomic masses: C=12 g mol−1C = 12 \text{ g mol}^{-1}, H=1 g mol−1H = 1 \text{ g mol}^{-1}, O=16 g mol−1O = 16 \text{ g mol}^{-1})

  1. A.52.17%Correct answer
  2. B.34.78%
  3. C.26.08%
  4. D.61.02%

Solution

Molar mass of C2H5OH=(2×12)+(6×1)+(1×16)=24+6+16=46 g mol−1C_2H_5OH = (2 \times 12) + (6 \times 1) + (1 \times 16) = 24 + 6 + 16 = 46 \text{ g mol}^{-1}. Mass of carbon in one mole =24 g= 24 \text{ g}. Mass percentage of carbon =(24/46)×100=52.17%= (24 / 46) \times 100 = 52.17\%.

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