Atoms · Class 12 · CBSE · Science Physics

What is the ratio of the frequency of revolution of an electron in the n=2 Bohr orbit to that in the n=1 Bohr orbit of a hydrogen atom?

Practice question from Atoms (Class 12 · CBSE · Science Physics), with the correct answer and a step-by-step solution.

medium · MCQ · Q-C70967

What is the ratio of the frequency of revolution of an electron in the $n=2$ Bohr orbit to that in the $n=1$ Bohr orbit of a hydrogen atom?

A. $1:4$
B. $1:8$ Correct answer
C. $8:1$
D. $4:1$

Solution

The frequency of revolution $f$ is given by $f = \frac{v}{2\pi r}$ . Since $v \propto \frac{1}{n}$ and $r \propto n^2$ , we get $f \propto \frac{1}{n^3}$ . Therefore, $\frac{f_2}{f_1} = \left(\frac{1}{2}\right)^3 = \frac{1}{8}$ .

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