Mechanical Properties of Fluids · JEE Preparation Physics

A cylindrical vessel filled with liquid is rotated about its vertical axis of symmetry with a constant angular velocity omega. The shape of the free…

Practice question from Mechanical Properties of Fluids (JEE Preparation Physics), with the correct answer and a step-by-step solution.

easy · MCQ · Q-D03898

A cylindrical vessel filled with liquid is rotated about its vertical axis of symmetry with a constant angular velocity ω\omega. The shape of the free surface of the liquid is a:

  1. A.Hemisphere
  2. B.Cone
  3. C.Paraboloid of revolutionCorrect answer
  4. D.Hyperboloid

Solution

The height yy of the liquid surface as a function of the radial distance rr from the axis of rotation is given by the balance of centrifugal force and gravity: dydr=ω2rg\frac{dy}{dr} = \frac{\omega^2 r}{g}. Integrating this yields y=ω2r22gy = \frac{\omega^2 r^2}{2g}, which is the equation of a parabola. Therefore, the free surface forms a paraboloid of revolution.

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