Coordination Compounds · Class 12 · CBSE · Science Chemistry

What is the correct crystal field stabilization energy (CFSE) for a d^4 configuration in an octahedral field with strong field ligands?

Practice question from Coordination Compounds (Class 12 · CBSE · Science Chemistry), with the correct answer and a step-by-step solution.

hard · MCQ · Q-F4C2F0

What is the correct crystal field stabilization energy (CFSE) for a d4d^4 configuration in an octahedral field with strong field ligands?

  1. A.-1.6 \Delta_o + PCorrect answer
  2. B.-0.6 \Delta_o + P
  3. C.-1.2 \Delta_o
  4. D.-0.4 \Delta_o + P

Solution

For a strong field ligand, pairing energy PP is less than Δo\Delta_o (P<ΔoP < \Delta_o). Thus, all 4 electrons pair up in the t2gt_{2g} orbitals. CFSE = 4(−0.4Δo)+1P=−1.6Δo+P4(-0.4 \Delta_o) + 1P = -1.6 \Delta_o + P.

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