Coordination Compounds · NEET Preparation Chemistry

The spin-only magnetic moment of [Fe(H2O)6]2+ is approximately:

Practice question from Coordination Compounds (NEET Preparation Chemistry), with the correct answer and a step-by-step solution.

medium · MCQ · Q-0A227D

The spin-only magnetic moment of [Fe(H2O)6]2+ is approximately:

  1. A.4.90 BMCorrect answer
  2. B.5.92 BM
  3. C.1.73 BM
  4. D.0.00 BM

Solution

[Fe(H2O)6]2+ has Fe2+ with a d6d^6 configuration. Water is a weak field ligand, so electrons remain unpaired in high spin: t2g4eg2t_{2g}^4 e_g^2, giving 4 unpaired electrons (n=4n = 4). μ=4(4+2)=24≈4.90\mu = \sqrt{4(4+2)} = \sqrt{24} \approx 4.90 BM.

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