Conic Sections · JEE Preparation Mathematics

For the parabola y^2 = -12x, the focus and directrix are respectively:

Practice question from Conic Sections (JEE Preparation Mathematics), with the correct answer and a step-by-step solution.

easy · MCQ · Q-0DD6EE

For the parabola y^2 = -12x, the focus and directrix are respectively:

  1. A.(-3, 0) and x = 3Correct answer
  2. B.(3, 0) and x = -3
  3. C.(0, -3) and y = 3
  4. D.(0, 3) and y = -3

Solution

Comparing y2=−12xy^2 = -12x with y2=4axy^2 = 4ax, we get 4a=−124a=-12, so a=−3a=-3. Therefore, the focus is (−3,0)(-3,0) and the directrix is x=3x=3.

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