Conic Sections · JEE Preparation Mathematics
The radius of the circle x^2 + y^2 - 6x + 8y + 9 = 0 is:
Practice question from Conic Sections (JEE Preparation Mathematics), with the correct answer and a step-by-step solution.
easy · MCQ · Q-45C5BB
The radius of the circle x^2 + y^2 - 6x + 8y + 9 = 0 is:
- A.2
- B.3
- C.4Correct answer
- D.5
Solution
Completing the squares gives . Therefore, the radius is .
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