Current Electricity · Class 12 · CBSE · Science Physics

A cell of emf E and internal resistance r is connected across an external resistance R. The maximum power is delivered to the external resistance whe…

Practice question from Current Electricity (Class 12 · CBSE · Science Physics), with the correct answer and a step-by-step solution.

medium · MCQ · Q-DA1BD8

A cell of emf EE and internal resistance rr is connected across an external resistance RR. The maximum power is delivered to the external resistance when:

  1. A.R = rCorrect answer
  2. B.R = 2r
  3. C.R = r/2
  4. D.R >> r

Solution

Power delivered to the external load is given by P=(ER+r)2RP = \left(\frac{E}{R+r}\right)^2 R. For maximum power, dPdR=0\frac{dP}{dR} = 0, which yields R=rR = r.

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