Moving Charges and Magnetism · NEET Preparation Physics

A long straight wire carries a current I. The magnetic field at a perpendicular distance r from the wire is B. If the current is doubled and the dist…

Practice question from Moving Charges and Magnetism (NEET Preparation Physics), with the correct answer and a step-by-step solution.

easy · MCQ · Q-95DBA0

A long straight wire carries a current II. The magnetic field at a perpendicular distance rr from the wire is BB. If the current is doubled and the distance is halved, the new magnetic field becomes:

  1. A.B/4B / 4
  2. B.B/2B / 2
  3. C.2B2B
  4. D.4B4BCorrect answer

Solution

Magnetic field of a long straight wire is B=μ0I2πrB = \frac{\mu_0 I}{2\pi r}. If I′=2II' = 2I and r′=r/2r' = r/2, then B′=μ0(2I)2π(r/2)=4(μ0I2πr)=4BB' = \frac{\mu_0 (2I)}{2\pi (r/2)} = 4 \left(\frac{\mu_0 I}{2\pi r}\right) = 4B.

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