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Moving Charges and Magnetism · NEET Preparation Physics

A rectangular loop of sides 10text{ cm} and 5text{ cm} carrying a current 2text{ A} is placed in a uniform magnetic field of magnitude 0.3text{ T}. T…

Practice question from Moving Charges and Magnetism (NEET Preparation Physics), with the correct answer and a step-by-step solution.

easy · MCQ · Q-ED1BE1

A rectangular loop of sides 10 cm10\text{ cm} and 5 cm5\text{ cm} carrying a current 2 A2\text{ A} is placed in a uniform magnetic field of magnitude 0.3 T0.3\text{ T}. The maximum torque acting on the loop is:

  1. A.3×10−3 N m3 \times 10^{-3}\text{ N m}Correct answer
  2. B.6×10−3 N m6 \times 10^{-3}\text{ N m}
  3. C.3×10−2 N m3 \times 10^{-2}\text{ N m}
  4. D.1.5×10−2 N m1.5 \times 10^{-2}\text{ N m}

Solution

Maximum torque τmax=NIAB\tau_{\text{max}} = NIAB. Here N=1N=1, area A=10 cm×5 cm=50×10−4 m2=5×10−3 m2A = 10\text{ cm} \times 5\text{ cm} = 50 \times 10^{-4}\text{ m}^2 = 5 \times 10^{-3}\text{ m}^2, I=2 AI = 2\text{ A}, and B=0.3 TB = 0.3\text{ T}. Thus, τmax=1×2×(5×10−3)×0.3=3×10−3 N m\tau_{\text{max}} = 1 \times 2 \times (5 \times 10^{-3}) \times 0.3 = 3 \times 10^{-3}\text{ N m}.

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